CLAT LLB Math Sample Question Paper Solved
1. Sonika invested an amount of Rs 5800 for 2 years. At what rate of compound interest will she get an amount of Rs 594.50 at the end of two years?
1) 5 pcpa
2) 4 pcpa
3) 6 pcpa
4) 8 pcpa
5) None of these
Ans: (1)
1) 5 pcpa
2) 4 pcpa
3) 6 pcpa
4) 8 pcpa
5) None of these
Ans: (1)
Solution;
6394.50/5800 = (1+R/100) square
441/400 = (1+R/100) square
(21/20) square = (1+R/100) square
21/20 = (1+R/100)
R= 5
2. If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51 . What is the original fraction?
1) 11/17
2) 11/15
3) 15/17
4) 13/15
5) None of these
Ans: (3)
Solution:
2.5x/4.5y = 25/51
x/y = 15/17
3. In how many different ways can the letters of the word 'BANKING' be arranged?
1) 5040
2) 2540
3) 5080
4) 2520
5) None of these
Ans: (4)
3. In how many different ways can the letters of the word 'BANKING' be arranged?
1) 5040
2) 2540
3) 5080
4) 2520
5) None of these
Ans: (4)
Solution;
7!/2! = 7x6x5x4x3= 2520
4. Meenal purchased a car for Rs 2, 50, 000 and sold it for Rs 3, 48, 000. What is the per cent profit she made on the car?
1) 40
2) 39.2
3) 38.4
4) 38
5) None of these
Ans: (2)
4. Meenal purchased a car for Rs 2, 50, 000 and sold it for Rs 3, 48, 000. What is the per cent profit she made on the car?
1) 40
2) 39.2
3) 38.4
4) 38
5) None of these
Ans: (2)
Solution:
98000 x 100/250000 = 39.2%
5. There are some parrots and some tigers in a forest. If the total number of animal heads in the forest is 858 and the total number of animal legs is 1,846, what is the number of parrots in the forest?
1) 845
2) 833
3) 800
4) Cannot be determined
5) 793
Ans: (5)
1) 845
2) 833
3) 800
4) Cannot be determined
5) 793
Ans: (5)
Hint; Apply Alligation and Mixture
7. By how much is 3/4 of 968 less than 7/8 of 1008?
1) 154
2) 146
3) 165
4) 158
5) 156
Ans: (5)
Solution:
1) 154
2) 146
3) 165
4) 158
5) 156
Ans: (5)
Solution:
3/4 of 968 =726
7/8 of 1008= 882
882 – 726 = 156
8. There are two numbers such that the sum of twice the first number and twice the second number is 100 and the sum of thrice the first number and twice the second number is 120. Which is the larger number?
1) 30
2) 12
3) 14
4) 35
5) None of these
Ans: (1)
3x + 2y = 120
2x + 2y = 100
So x = 20 and y = 30
9. When-all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed?
1) 25
2) 42
3) 36
4) 32
5) None of these
Ans: (3)
Solution:
9. When-all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed?
1) 25
2) 42
3) 36
4) 32
5) None of these
Ans: (3)
Solution:
54 x 30/45 = 36
10. The ratio of the present ages of Anju and Sandhya is 13: 17. Four years ago the ratio of their ages was 11: 15. What will be the ratio of their ages six years hence?
1) 3 : 4
2) 7 : 8
3) 5 : 4
4) 6 : 5
5) 4 : 5
Ans: (5)
1) 3 : 4
2) 7 : 8
3) 5 : 4
4) 6 : 5
5) 4 : 5
Ans: (5)
13x - 4/ 17x – 4 = 11/15
X = 2
Anju’s Present age = 26
Sandhya’s Present age = 34
six years hence = 32 & 40 i.e. 4 : 5
11. The average age of 80 boys in a class is 15. The average age of a group of 15 boys in the class is 16 and the average age of another 25 boys in the class is 14. What is the average age of the remaining boys in the class?
1) 15.25
2) 14
3) 14.75
4) Cannot be determined
5) None of these
Ans: (1)
Total age (sum) of all 80 students = 80 x 15 = 1200
11. The average age of 80 boys in a class is 15. The average age of a group of 15 boys in the class is 16 and the average age of another 25 boys in the class is 14. What is the average age of the remaining boys in the class?
1) 15.25
2) 14
3) 14.75
4) Cannot be determined
5) None of these
Ans: (1)
Total age (sum) of all 80 students = 80 x 15 = 1200
Total age (sum) of 15 students = 15 x 16 = 240
Total age (sum) of 25 students = 25 x 14 = 350
Total age (sum) of remaining 40 students = 1200 – ( 240 + 350 ) = 610
Average of remaining 40 students = 610/40 = 15.25
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